[java论坛] springmvc restful开发

package sy.controller;

import javax.servlet.http.HttpServletRequest;

import org.springframework.beans.factory.annotation.Autowired;

import org.springframework.stereotype.Controller;

import org.springframework.web.bind.annotation.RequestMapping;

import sy.model.User;

import sy.service.UserServiceI;

//springMvc的应用

//加上@Controller表示这是一个控制器类，将它加入到spring-mvc的框架中了

//在spring-mvc.xml中<context:component-scan base-package="sy.controller" />就能扫描到

@Controller

//访问地址的注解@RequestMapping

//在web.xml中配置了<url-pattern>*.do</url-pattern>所以("/userController.do")也不要写

@RequestMapping("/userController")

public class UserController {

private UserServiceI userService;

public UserServiceI getUserService() {

return userService;

}

@Autowired

public void setUserService(UserServiceI userService) {

this.userService = userService;

}

@RequestMapping("/showUser")

public String showUser(Integer id, HttpServletRequest request) {

//因为在spring-mvc.xml 31行配置了 p:suffix=".jsp"

//所以返回是showUser.jsp 文件的后缀.jsp不要写

User u = userService.getUserById(id);

request.setAttribute("user", u);

return "showUser";

}

}

浏览器访问效果：

代码修改后：

@RequestMapping("/showUser/{id}")

public String showUser(@PathVariable Integer id, HttpServletRequest request) {

//因为在spring-mvc.xml 31行配置了 p:suffix=".jsp"

//所以返回是showUser.jsp 文件的后缀.jsp不要写

User u = userService.getUserById(id);

request.setAttribute("user", u);

return "showUser";

}

浏览器地址：http://127.0.0.1:8080/mybatis/userController/showUser/2.do

效果：

也可以这这种方式：

@RequestMapping("/{id}/showUser")

public String showUser(@PathVariable Integer id, HttpServletRequest request) {

//因为在spring-mvc.xml 31行配置了 p:suffix=".jsp"

//所以返回是showUser.jsp 文件的后缀.jsp不要写

User u = userService.getUserById(id);

request.setAttribute("user", u);

return "showUser";

}

浏览器地址：http://127.0.0.1:8080/mybatis/userController/1/showUser.do

效果：